Class 10 Science Chapter 1 Gravitation Questions & Answers | Maharashtra Board

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Class 10 Science Chapter 1 Gravitation Questions & Answers | Maharashtra Board
Maharashtra Board • Standard 10

Class 10 Science
Gravitation Solutions

Premium solved exercise for Science & Technology Part 1. Learn mass, weight, Kepler’s laws, and numerical problems with our expert guidance.

EARTH MOON
10 Key Concepts
07 Solved Numericals
10 Quiz MCQs
100% Verified Data

Chapter Overview

Chapter 1: Gravitation introduces the universal force that keeps planets in orbit and objects grounded. We cover Newton's laws, Kepler's observations, and the critical distinction between mass and weight.

Exercise Questions & Answers

1
Study the table entries and match them appropriately.
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ConceptCorrect UnitCorrect Property
MasskgMeasure of inertia
WeightNZero at centre
Acc. due to gravitym/s²Depends on height
Grav. constant (G)N m²/kg²Same in the entire universe
💡 Reminder: $G$ is universal, while $g$ varies by position!

Q2. Answer the following:

2a
Difference between Mass and Weight.
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PropertyMassWeight
DefinitionThe amount of matter in an object.The gravitational force acting on the object.
SI UnitkgNewton (N)
FormulaScalar quantityW = mg (Vector)
LocationRemains constant everywhere.Changes depending on local gravity.
2c
State Kepler's Three Laws.
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  1. Law of Orbits: Every planet revolves around the Sun in an elliptical orbit, with the Sun at one of the foci.
  2. Law of Areas: The line joining the planet and the Sun sweeps equal areas in equal intervals of time.
  3. Law of Periods: The square of its period of revolution ($T^2$) is directly proportional to the cube of the mean distance ($r^3$) of a planet from the Sun: $T^2 \propto r^3$.
3
Why is 'g' zero at the centre of the Earth?
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As we go inside the earth, the mass of the earth that contributes towards gravity decreases. At the exact centre, the mass of the earth "pulling" from all directions is balanced. Mathematically, in the formula $g = \frac{GM}{R^2}$, as we reach the centre, effective $M$ becomes zero because we are surrounded uniformly by mass. Thus, net acceleration due to gravity $g = 0$.

Question 5: Gravitation Numericals

5a
An object takes 5s to reach ground from 5m. Find g.
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Given Data:
  • Height ($s$) = 5 m
  • Time ($t$) = 5 s
  • Initial velocity ($u$) = 0
s = ut + ½ g t²
5 = 0 + ½ × g × (5)²
5 = ½ × g × 25
10 = 25g
g = 10 / 25 = 0.4 m/s²

Final Answer: g = 0.4 m/s²

5c
Object mass 5kg, Weight 49N on Earth. Values on Moon?
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Mass remains same everywhere. So, Mass on Moon = 5 kg.

Gravity on moon is 1/6th of earth gravity.

Weight on Moon = Weight on Earth / 6
Weight = 49 / 6 ≈ 8.17 N

Final Answer: Mass = 5 kg, Weight = 8.17 N

Project: Weight Calculator

Enter your weight on Earth to calculate your weight on the Moon and Mars!

PlanetWeight Value (approx)
Moon (1/6g)10.00 kg
Mars (0.38g)22.80 kg

Formula Hub

Weight Formula
W = mg

m = mass, g = acc. due to gravity

Universal Gravitation
F = G m₁m₂ / r²

The base law of attraction.

Orbital Proportionality
T² ∝ r³

Kepler's 3rd Law.

Chapter Quiz

Ready to test your knowledge on Gravitation?

Frequently Asked Questions

What is Free Fall?

The motion of an object where gravity is the only force acting on it is called free fall.

What is escape velocity?

The minimum speed needed for an object to escape Earth's gravitational pull for good. (11.2 km/s approx)

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